(2x-1)x^2-4(2x-1)=0

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Solution for (2x-1)x^2-4(2x-1)=0 equation: 


Simplifying
(2x + -1) * x2 + -4(2x + -1) = 0

Reorder the terms:
(-1 + 2x) * x2 + -4(2x + -1) = 0

Reorder the terms for easier multiplication:
x2(-1 + 2x) + -4(2x + -1) = 0
(-1 * x2 + 2x * x2) + -4(2x + -1) = 0
(-1x2 + 2x3) + -4(2x + -1) = 0

Reorder the terms:
-1x2 + 2x3 + -4(-1 + 2x) = 0
-1x2 + 2x3 + (-1 * -4 + 2x * -4) = 0
-1x2 + 2x3 + (4 + -8x) = 0

Reorder the terms:
4 + -8x + -1x2 + 2x3 = 0

Solving
4 + -8x + -1x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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